Area of the sector
, where
is the radius of the circle and
is the central angle.
Find the angle rotated by the sprinkler.
\Area covered by the water sprinkler
square yards.
Radius of the circle
yd.
Consider
.
Substitue
and
in above formula.

Thus, the angle rotated by the sprinkler is 0.89 radian.
\ \The angle rotated by the sprinkler is 0.89 radian.