$\"\"$

\

The circle equation is $\"\"$ .

\

The standard form of a circle equation is $\"\"$ , where center $\"\"$ and radius $\"\"$ .

\

Convert the given circle equation into standard form by using completing square method.

\

$\"\"$ Circle equation $\"\"$ .

\

$\"\"$

\

To complete the square add $\"\"$ to each side of equation.

\

$\"\"$ $\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

Compare it with standard form.

\

Center $\"\"$ and $\"\"$ .

\

$\"\"$

\

$\"\"$ Graph the circle with center $\"\"$ and radius $\"\"$ .

\

Find four points " radius away from the center in the up, down, left and right direction".

\

Up $\"\"$ , down $\"\"$ , left $\"\"$ and right $\"\"$ .

\

Draw the coordinate plane.

\

1). Plot the center at $\"\"$ .

\

2). Plot four points " radius away from the center in the up, down, left and right direction".

\

3). Sketch the circle.

\

\

$\"\"$

\

$\"\"$ The circle equation is $\"\"$ .

\

Find the intercepts.

\

First find the $\"\"$ -intercept, by substituting $\"\"$ in the original equation.

\

$\"\"$

\

Solve for $\"\"$ .

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$ -intercept is $\"\"$ .

\

$\"\"$

\

Next find the $\"\"$ -intercept let $\"\"$ in the original equation.

\

$\"\"$

\

Solve for $\"\"$ .

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

Take square root each side.

\

$\"\"$

\

$\"\"$

\

In this case roots are imaginary, so there is no $\"\"$ -intercepts.

\

$\"\"$

\

$\"\"$ Center $\"\"$ and $\"\"$ .

\

$\"\"$ The circle graph:

\

\

$\"\"$ Intercept is $\"\"$ .