Find
.
The function
.
The point
is on the circle
.
Compare the equation with
.
Radius of the circle
.
Substitute
and
in the above equation.


Since the point lies in second quadrant, the value of
.
The point
is on a circle of radius
.
From the figure, angle
lies in third quadrant.
.
\
Half-angle identity :
.
Apply the formula :
.
Substitute
,
and
in
.



Therefore,
.
.