$\"\"$

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The focus is at $\"\"$ .

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Directrix of the line is $\"\"$ .

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Since the directrix of the line is $\"\"$ then the parabola is vertical.

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Standard form of the vertical parabola is $\"\"$ , where $\"image\"$ is vertex.

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If $\"image\"$ then the parabola opens to the left and $\"image\"$ parabola opens to the right.

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Directrix is $\"\"$ and focus at $\"\"$ .

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$\"\"$

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Focus $\"\"$ .

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$\"\"$

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Directrix $\"\"$

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$\"\"$

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Solve the equations $\"\"$ and $\"\"$ :

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$\"\"$

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$\"\"$

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Therefore, the vertex of the parabola is $\"\"$ .

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$\"\"$

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Find the value of $\"\"$ .

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Substitute $\"\"$ in equation $\"\"$ .

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$\"\"$

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Substitute the values $\"\"$ and $\"\"$ in standard form.

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$\"\"$

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Therefore the parabola equation is $\"\"$ .

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$\"\"$

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Latus rectum is the line segment of a parabola perpendicular to axis which has both ends on the curve.

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The parabola equation is $\"\"$ .

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Obtain the points define the latus rectum, consider the $\"\"$ coordinate of focus as $\"\"$ .

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$\"\"$

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$\"\"$

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The latus rectum points $\"\"$ and $\"\"$ .

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$\"\"$

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Graph :

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(1) Draw the coordinate plane.

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(2) Graph the parabola equation $\"\"$ .

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(3) Plot the vertex, focus, and the two points $\"\"$ and $\"\"$ .

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(4) Draw the directrix line.

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(5) Connect the plotted points with smooth curve.

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$\"\"$

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$\"\"$

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The parabola equation is $\"\"$ .

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The latus rectum points $\"\"$ and $\"\"$ .

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Graph of the parabola is

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$\"\"$ .