The function .

Rewrite the function as .

(a)

Substitute the point in the function.

Since the above statement is true, the point is on the graph of .

(b)

Find .

The function is .

Substitute in .

.

The point   is on the graph of .

(c)

Find the values of .

The function is .

Here .

Apply zero product property.

and

and

if   then and .

The points  and are on the graph of .

(d)

The function is .

Above function is simply fraction and in a fraction the denominator cannot be equal to zero because it would be undefined.

To find which number make the fraction undefined create an equation where the denominator not equal to zero.

The domain of is .

(e)

Find the -intercept.

The function is .

Find the -intercepts by substituting in given function.

Take square root each side.

and .

Since the roots are imaginary, in this case there is no -intercepts.

(f)

Find the  -intercepts.

The function is .

Find the -intercepts by substituting in given function.

.

The -intercept is  .

The point is on the graph of .

(a) The point   is on the graph of . 

(b)  , the point   is on the graph of .

(c) The values are and .

The points and are on the graph of .

(d)  The domain of is .

(e) There is no -intercepts.

(f) The -intercept is .