$\"\"$

The equation is " $\"\"$ ".

Directrix is perpendicular to the polar axis at a distance p units below the pole.

Compare the equation to $\"\"$ .

Then ep = 3, e = 1, So $\"\"$ .

Directrix $\"\"$ .

$\"\"$ , then the conic is a parabola.

One focus is at the pole, and the directix is perpendicular to the pair axis,

a distance of p = 3 units to the right of the pole, let $\"\"$ . $\"\"$

The vertices of the parabola are $\"\"$ and $\"\"$ .

The midpoint of the vertices, $\"\"$ in polar coordinates, is the center of parabola.

Then vertices at $\"\"$ and $\"\"$ in polar coordinates are $\"\"$ and $\"\"$ .

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

$\"\"$

To graph of the parabola.

$\"graph$

$\"\"$

The conic is a parabola, vertices at $\"\"$ , $\"\"$ and $\"\"$ .

$\"graph$