\
n( AUB ) = 60, n( A∩B ) = 40 and n(A) = n(B). \ \
\By using counting formula : n( AUB ) = n(A) + n(B) − n( A∩B ) \ \
\Substitute : n( AUB ) = 60 , n( A∩B ) = 40. \ \
\60 = n(A) + n(B) − 40 \ \
\Substitute n(A) = n(B) \ \
\60 = n(A) + n(A) − 40 \ \
\60 = 2n(A) − 40 \ \
\2n(A) = 40 + 60 \ \
\
(Divide each side by 2)
n(A) = 50
\\
\
n(A) = 50