$\"\"$

The given limit is $\"\"$ .

Compare the limit with $\"\"$ , So $\"\"$ .

Now choose values of x close to 3, arbitrarily starting with 2.99.

Then choose values of x > 3, starting with 3.01, that get closer to 3.

Finally evaluate f at each choice to obtain table below.

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

\ x \	\ 2.99 \	\ 2.999 \	\ 2.9999 \	\ $\"\"$ \	\ 3.0001 \	\ 3.001 \	\ 3.0 \
\ $\"\"$ \	2.003344	\ 2.000333444 \	\ 2.000033334444 \	\ $\"\"$ \	\ 1.99996666 \	\ 1.999666 \	\ 2.0 \

Now from above table we infer that as x gets closer to 3 the value of f(x) closer to 2..

Then the value of $\"\"$ .

$\"\"$

To check the solution of $\"\"$ .

Apply formula: $\"\"$ .

$\"\"$

Substitute x = 3.

$\"\"$

$\"\"$ .