\
The piecewise function is
.
Consider
.

(a)
\All possible values of
for which the function is mathematically correct is the domain of a function.
The domain set of
is
.
Domain in interval notation
.
\
(b)
\Find the intercepts.
\Find the
-intercept by substituting
.
If
then the function is
.
Substitute
in
.

The value of
which is not to be considered because
.
\
If
then the function is
.
Substitute
in
.

The value of
which is not to be considered because
.
There is no
-intercepts.
Find the
-intercept by substituting
.
The function
is defined at
.
Substitute
in
.

The function
is not defined at
.
The
- intercept is
.
(c)
\Draw the table of different values of
for
.
![]() | \
\
| \
\
| \
![]() | \
\
| \
\
| \
![]() | \
\
| \
\
| \
\
![]() | \
\
| \
\
| \
![]() | \
\
| \
\
| \
![]() | \
\
| \
\
| \
Graph :
\1). Draw a coordinate plane.
\2). Plot the points found in the table and connect the plotted points
\3). Label the intercept points.
\\
(d)
\All possible values of
is range of a function.
Observe the graph: The range of function is
.
The range in interval notation
.
(e ) The function discontinous at
.
(a) Domain in interval notation
.
(b) The intercept is
.
(c) Graph of the function
:
(d) Range in interval notation
.
(e) The function is discontinous at
.