The equation is
and the point is
.
Consider
.
Differentiate on each side with respect to
.


Slope of the tangent line at
.

Slope of the tangent line is
.
Point slope form of line equation is
.
Substitute
and
in the above equation.

Tangent line is
.
The slope of the tangent line is perpendicular to the normal line slope.
\slope of tangent line*slope of normal line is equal to
.

Point slope form of line equation is
.
Substitute
and
in the above equation.

Normal line equation is
.
The equation of circle with center
and radius between these two circles
is
.

Differentiate on each side with respect to
.



Substitute
.


Substitute
in the above equation.


Substitute
in the circle equation 

Circle passes through the point
.


Roots of the quadratic equation is
.
Then,
\
Therefore
and
.
Substitute
in
.

Substitute
in
.
.
Circle equations are
and
.
Graph:
\Graph both the circle equations, curve, tangent line, normal line and point.
\
Tangent line equation is
.
Normal line equation is
.
Circle equations are
and
.