The equation is
and points are
and
.
The equation is
.
Apply derivative on each side with respect to
.

.
.
Consider the point
.
The derivative of the equation
at the point
is the slope of the line.
.
The line equation is
.
Substitute
and
in the line equation.

The tangent line equation is
.
Normal line is perpendicular to tangent line then,
\slope of tangent line
slope of normal line is equal to
.
Let slope of the normal as
.
Therefore,
.
.
point slope form of line equation is
.
Substitute
and
in the above equation.

The normal line equation is
.
The equation is
.
Apply derivative on each side with respect to
.

.
.
Consider the point
.
The derivative of the equation
at the point
is the slope of the line.
.
The line equation is
.
Substitute
and
in the line equation.


The tangent line is
.
Normal line is perpendicular to tangent line then,
\slope of tangent line
slope of normal line is equal to
.
Let slope of the normal as
.
Therefore, 
.
point slope form of line equation is
.
Substitute
and
in the above equation.


The normal line equation is
.
\
Graph:
\Graph the conic equation
.
Graph the tangent line equations
and
.
Graph the normal line equations
and
.

A the point
:
The tangent line equation is
.
The normal line equation is
.
As the point
:
The tangent line is
.
The normal line equation is
.
Graph:
\Graph of the conic equation
, the tangent line equations
and
and the normal line equations
and
is
.