The function is
,
.
(a)
\Graph :
\Sketch the function
over
.

(b)
\The slope of the secant line through
and
is






To find the secant line equation, use the point - slope form of line equation.
\The point - slope form of line equation is
.
Consider one point is
.

Graph :
\Sketch the function
and secant line
.

(c)
\The function satisfy the condition for mean value theorem, therefore there exist at least one number
in the
, such that
.

Apply derivative with respect to
.


The values of
are
and
.
The function two tangent line in the given interval.
\First tangent line :
\The point of tangency is
.

The point of tangency is
.
Slope of tangent
. [Since secant line is parallel to tangent line]
The point - slope form of line equation is
.

Second tangent line :
\The point of tangency is
.

The point of tangency is
.
Slope of tangent
. [Since secant line is parallel to tangent line]
The point - slope form of line equation is
.

Graph :
\Sketch the function
, secant line
and tangent lines
and
.

(a) Graph of the function
is

(b) The secant line equation
.
Graph of the secant line
is

(c) The tangent line equations are
and
.
Graph of the tangent line are
and
is
.