The function is
and interval is
.
Find the intercepts :
\To find the
- intercept, substitute
in the function.

Solve
in the interval
.

and 
and
.
doesnot exist for real values of
.
The solutions of
are
,
and
in the interval
.
Therefore, the
- intercepts are
,
and
.
To find the
-intercept, substitute
in the function.


The
- intercept is
.
Find the relative extrema for the function
:
Consider
.
Differentiate on each side with respect to
.


To find the critical number, make
.

and 
and 
The solutions of
are
and
in the interval
.
There is no solution for
in the interval
.
Thus, the critical points occur at
and
.
If
, then
.
If
, then
.
The relative maximum is
.
The relative minimum is
.
Find the points of inflection :
\ Consider
.
Derivative on each side with respect to
.

To find inflection points, equate
to zero.

and 
and 
,
, and
.
The solutions of
are
,
and
in the interval
.
The solutions of
are
and
in the interval
.
The solutions of
are
and
in the interval
.
If
, then
.
If
, then
.
If
, then
.
If
, then
.
If
, then
.
If
, then
.
If
, then
.
The inflection points are
,
,
,
,
,
, and
.
Find the asymptotes :
\The function is
.
Vertical asymptote :
\The line
is a vertical asymptote if
.

Therefore, there is no vertical asymptote for the function
.
Horizontal asymptote :
\The line
is a horizontal asymptote if
.

Limit does not exist.
\Therefore, there is no horizontal asymptote for the function
.
Find intervals of increase or decrease :
\Consider the test intervals as
,
and
.
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
![]() | \
\
| \
Increases, point of inflection | \
![]() | \
![]() | \
![]() | \
\
| \
Decreases, concave downward | \
![]() | \
![]() | \
![]() | \
\
| \
Increases,point of inflection | \
\
The graph is increases on the intervals
and
.
The graph is decreases on the interval
.
Using all the above characteristics of the function, graph the function
in the interval
.
Graph :
\Draw a coordinate plane.
\Graph the function
in the interval
.
.
The function is
in the interval
.
Graph :
\Using Graphing utility draw the graph of the function
in the interval
..
.
Observe the above two graphs : The graphs represents the same function, i.e,
.
Graph of the function
in the interval
:
.