$\"\"$

\

The function is $\"\"$ and the interval $\"\"$ .

\

Using mid point theorem:

\

The area is $\"\"$ .

\

Consider $\"\"$ . Take $\"\"$ .

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$\"\"$ .

\

Substitute $\"\"$ in $\"\"$ .

\

$\"\"$ .

\

$\"\"$ .

\

Substitute $\"image\"$ values from $\"\"$ to $\"\"$ .

\

$\"\"$ .

\

$\"\"$ .

\

$\"\"$ .

\

$\"\"$ .

\

$\"\"$ . $\"\"$

\

Using mid point theorem:

\

Area = $\"\"$

\

$\"\"$

\

$\"\"$ sq-units.

\

Graph the region:

\

$\"\"$ .

\

$\"\"$

\

Graph the region when $\"\"$ .

\

$\"\"$ .

\

Observe the graph:

\

The approximate area when $\"\"$ is $\"\"$ .

\

Graph the region when $\"\"$ .

\

$\"\"$ .

\

Observe the graph:

\

The approximate area when $\"\"$ is $\"\"$ .

\

Graph the region when $\"\"$ .

\

$\"\"$ .

\

Observe the graph:

\

The approximate area when $\"\"$ is $\"\"$ .

\

Graph the region when $\"\"$ .

\

$\"\"$ .

\

Observe the graph:

\

The approximate area when $\"\"$ is $\"\"$ .

\

Complete the table:

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$
Approximate area	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$

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$\"\"$

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$
Approximate area	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$

\