The function is .

Let the tangent point as .

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Apply derivative on each side with respect to .

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Slope of the tangent is derivative of the function at the given point. 

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Tangent and normal lines are perpendicular to each other.

Product of the slopes of the perpendicular lines is .

Slope of the normal line is

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Normal line passes through the origin.

Slope of the line joining points of and is .

Therefore,

At lies on the curve, .

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Solve the equation using graphing utility.

Graph the curve .

Observe the graph, root of the equation is .

Therefore, .

If then, .

Therefore the point is .

  is the point where the normal line to the curve is passes through the origin.