$\"\"$

\

The equation is $\"\"$ and the point is $\"\"$ .

\

Consider $\"\"$ .

\

Apply the derivative with respect to $\"\"$ .

\

$\"\"$

\

Derivative of inverse trigonometric function $\"\"$ .

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

The slope of the tangent line is the derivative of the function at the point $\"\"$ . $\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$ .

\

Thus, the slope of the tangent line is $\"\"$ .

\

$\"\"$

\

The point-slope form of line equation is $\"\"$ .

\

Substitute $\"\"$ and the point $\"\"$ in above equation.

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$ .

\

$\"\"$

\

The tangent line equation is $\"\"$ .