The function is
.
Consider
.
The value of
lies in the interval
.
.
The point
does not lie on the graph
with domain
.
It does not contradict to the definition of the inverse trigonometric function.
\
is not a one-to-one function over its complete domain.
Therefore to find its inverse, restrict the domain over the interval
where it is one-to-one.
Domain of
is
and range is
.
does not belong to the range
.
No, the point
do not lie on the graph
.
It does not contradict to the definition of the inverse trigonometric function.