The differential equation is
.
The general solution is
.
Initial conditions:
\
and
when
.
Consider
.
Differentiate with respect to
.

The first derivative is
.
Differentiate with respect to
.

Substitute the values of
in
.

Therefore, the differential equation condition is satisfied.
\To find out the particular solution substitute
in
.

Consider the general solution
.
Substitute
in the general solution.

The particular solution is
.

Quotient rule of logarithm:
.
.
The particular solution is
.