$\"\"$

The integral is $\"\"$ .

$\"\"$ is improper when the denominator $\"\"$ .

$\"\"$

$\"\"$ .

The integral is undefined at $\"\"$ , which lies in the interval $\"\"$ .

$\"\"$ has infinite discontinuity at $\"\"$ .

$\"\"$

If $\"\"$ is continuous on the interval $\"\"$ , except for some $\"\"$ in $\"\"$ at which $\"\"$ has an infinite discontinuity, then $\"\"$ , the limit exists then function is convergent.

$\"\"$

Therefore, the integral is converges.

$\"\"$

$\"\"$ has infinite discontinuity at $\"\"$ .

The integral converges.