The integral is
.
.
If
is continuous on the interval
then
is convergent.
.
Solve the integral by using integration by parts of integration.
\Apply integration by parts formula
.
Consider
.
Apply derivative on each side with respect to
.
.
Consider
.
Apply Integral on each side.
\
.
.
Again apply integration by parts.
\
Apply the limits.
\

Therefore, the integral
is converges to
.
The improper integral
is converges to
.