The integral is
.
is discontinuous at
.
If
is continuous on the interval
, except for some
in
at which
has an infinite discontinuity, then
.
The improper integral on the left diverges if either of the improper integrals on the right diverges. \ \
\
.

Apply formula:
.







.
.
Therefore, the series is converges to
.
Graph:
\Graph the integrand
.

Observe the graph:
\Integration capabilities:
.
The improper integral
is converges to
.