$\"\"$

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The integral is $\"\"$ .

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Rewrite the integral as $\"\"$ .

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The Comparison Test:

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Suppose that $\"\"$ and $\"\"$ are two continuous functions and $\"\"$ on the interval $\"\"$ .

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(i) If $\"\"$ is convergent, then $\"\"$ is also convergent.

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(ii) If $\"\"$ is divergent, then $\"\"$ is also divergent.

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The dominant part of the numerator is 1 and the dominant part of the denominator is $\"\"$ .

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Now compare the given function with the function $\"\"$ .

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$\"\"$

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Observe that $\"\"$ .

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$\"\"$

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Consider the function is $\"\"$ .

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$\"\"$

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Apply formula $\"\"$

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$\"\"$ is convergent if $\"\"$ and divergent if $\"\"$ .

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$\"\"$

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It is divergent because $\"\"$ .

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Therefore, $\"\"$ is also divergent by Comparison Test.

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$\"\"$ is divergent.

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$\"\"$

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$\"\"$ is divergent.