The function is
.
(a)
\Find the geometric power series of the function.
\
.
The series is in the form of geometric series.
\The general form of geometric series is
.
Substitute
and
.

.
The series is converges when
.


.
Therefore, the power series is
and is converges in the interval
.
(b)
\Solve the series by long division method.
\The function is
.
The series is
.

The power series is
and is converges in the interval
.