The parametric equation of path of projectile motion is
and
.
Here
is the initial velocity.
is the angle made with respect to ground.
is the height above the ground.
(a)
\Eliminate parameter
from the parametric equations.
Consider
.

.
Substitute
in
.



The rectangular equation is 
(b)
\The rectangular equation is
.
Compare the equation with 
Here
.

Find
.


Initial velocity is
.
The parametric equation of path of projectile motion is
and
.
Substitute
,
and
.
and 
and
.
The parametric equations are
and
.
(c)
\The parametric equations are
and
.
The rectangular equation is
.
Graph:
\Graph the parametric equations
and
.
Graph the rectangular equation
.

Observe the graph:
\The graphs obtained parametric equations is equal to the rectangular equations.
\(d)
\The rectangular equation is
.
Find the maximum height.
\Maximum height of a object in a projectile motion occurs when vertical component of velocity is zero.
\In simple, this is a point where we draw the line of symmetry.
\Find the range.
\Range is the horizontal distance travelled during projectile motion.
\Graph:
\Graph the rectangular equation
.

Observe the graph:
\Maximum height is
.
Range is
.
(a) The rectangular equation is 
(b)
,
and
.
The parametric equations is
and
.
(c) The graphs obtained parametric equations is equal to the rectangular equations.
\(d)
\Maximum height is
.
Range is
.