Gradient of the function:
\
.
The gradient of the vector is normal to the level surfaces.
\
(a)
\The equations are
,
and the point is
.
Rewrite the equation
as
.
Consider
.
Find gradient of the function
.
.
Substitute the point
in above equation.

Rewrite the equation
as
.
Consider
.
Find gradient of the function
.
.
Substitute the point
in above equation.
The cross product of these two gradients is a vector that is tangent to
\both surfaces at the point
.

Symmetric equations:
\
(b)
\Dot product is
.

Two vectors are orthogonal if and only if the dot product is zero.
\Since
, the vectors are not orthogonal.
(a) Symmetric equations are
.
(b) The cosine angle is
, the surfaces are not orthogonal.