The equation of elliptical region is
and the point on edge of the shadow is
.
Observe the graph.
\The edge of the shadow is tangent to the curve.
\Slope of the tangent is derivative of the curve.
\Consider equation of ellipse
.
Differentiate on each side with respect to
.




.
Assume that the ellipse has the tangent at the point
.
Slope of the tangent at
.
.
Point-slope form of line equation:
.
Substitute
and
in the above formula.
.
The above line passes through the point
.
So it will satisfy the above tangent line equation.
\
The point
lies on ellipse.
Therefore we have,
.
Substitute
in
.
.
.
Substitute
in
.

Thus the points are
and
.
The lamp is located in positive
- axis direction, so we consider the point
only.
Slope of the tangent at
is
.
Point-slope form of line equation:
.
Substitute
and
in the point-slope formula.

From the graph, it is observe that lamp is located 3-units right from the
-axis.
And assume that lamp is located
units above
-axis.
Thus the coordinates of the point at which lamp is located are
.
The tangent line
passes through the point
.
Hence it will satisfy the line equation.
\
Therefore, the lamp is situated 2 units above the
-axis.
The lamp is situated 2 units above the
-axis.