\
The function is
.
Differentiate
on each side with respect to
.

Apply the mean value theorem.
\
.
\
Substitute
in
.

The interval is
which does not include
.
Thus, there is no value
, such that
.
It does not contradict the mean value theorem because the function is discontinuous at
thus it does not differentiable in the given interval.
\
The function
is discontinuous at
.