(a)
\The function is
.
Differentiate
on each side with respect to
.

Find the critical points.
\Since
is a polynomial it is continuous at all the point.
Therefore the critical points exist when
.
Equate
to zero.

and
and 
and
and
.
The critical points are
,
and
.
The test intervals are
,
,
and
.
| Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
| \
| \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function is increasing on the interval
.
The function is decreasing on the intervals
and
.
(b)
\Find the local maximum and local minimum.
\The function
has a local minimum at
, because
changes its sign from negative to positive.
Substitute
in
.

Local minimum is
.
The function
has a local maximum at
, because
changes its sign from positive to negative.
Substitute
in
.

Local maximum is
.
(c)
\
.
Differentiate
on each side with respect to
.
\
Find the inflection points.
\Equate
to zero.
and
and 
and
and
.
The inflection point are at
,
and
.
Substitute
in
.

Substitute
in
.

Substitute
in
.

The test intervals are
,
,
and
.
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
\
| \
Down | \
| \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
\
| \
Down | \
The graph is concave up on the intervals
and
.
The graph is concave down on the intervals
and
.
The inflection points are
,
and
.
(d)
\Graph :
\Graph the function
:

(a)
\Increasing on the interval
.
Decreasing on the intervals
and
.
(b)
\Local maximum is
.
Local minimum is
.
(c)
\Concave up in the intervals
and
.
Concave down in the intervals
and
.
Inflection points are
,
and
.
(d)
\Graph of the function
is
.