\
The function is
.
(A)
\Domain :
\The function is
.
All possible values of
is the domain of the function.
Denominator of the function should not be zero
\
The domain of the function
is
.
\
(B)
\Intercepts :
\To find the
-intercepts, substitute
in the function.
.
Therefore the
-intercept is
.
To find the
-intercepts, substitute
in the function.

Therefore the
-intercept is
.
\
(C)
\Symmetry :
\Substitute
in the function.
.

Hence
.
Therefore the function
is an odd function.
\
(D)
\Asymptotes :
\Horizontal asymptote :
\
Therefore the horizontal asymptote is
.
Vertical asymptote :
\Vertical asymptote appears when the function is not defined.
\
Therefore the vertical asymptote are
and
.
\
(E)
\Intervals of increase or decrease :
\The function is
.
Differentiate on each side with respect to
.


is never zero and the function is negative for the domain of
.
Therefore
is decreasing over its domain.
\
(F)
\Local Maximum and Minimum values :
\From (E) it is clear that the function is only decreasing.
\Therefore is no local minimum or maximum values.
\\
(G)
\Concavity and point of inflection :
\
.
Differentiate
on each side with respect to
.

\
Find inflection point by equating
to zero.

Inflection point is
.
But at
and
, the function is undefined,hence consider those points also.
Split the intervals into
,
,
and
.
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Down | \
![]() | \
| \
\
| \
\
\ Up \ | \
![]() | \
![]() | \
\
\ | \
Down | \
![]() | \
![]() | \
![]() | \
Up | \
The graph is concave up in the interval
,
.
The graph is concave down in the interval
and
.
\
(H)
\Graph :
\Graph of the function
:
\
(A) The domain of the function
is
.
\
(B)
-intercept is
and
-intercepts are
.
(C) No symmetry.
\(D) The horizontal asymptote is
and the vertical asymptotes are
and
.
(E) Decreasing on
,
and
.
(F) There is neither local minimum nor local maximum.
\(G) Concave up on
and
.
concave down on
and
.
(H) Graph of the function
is