The integral is
and number of sub intervals are
.
Mid point Rule:
,
where width of the interval :
and
.
Here the function is
.
Width of the interval :
.
The end points of four sub intervals are
and 
The mid points are
and
.
Mid Point rule :
.
Calculate the corresponding values of the function.
\
.
.
.
.
.
Substitute the corresponding values in
.

.
.