\
The integral is
.
Here integrand function is
and the interval is
.
Find the absolute minimum and maximum values in the interval
.
.
Differentiate on each side with respect to
.
.
Find the critical number by equating
to zero.

Hence there is only one number in the interval
.
Find the value of the function at the critical number
.

Find the value of the function at the end points at
.


Therefore, absolute minimum in the
is
.
Absolute maximum in the
is
.
.
Comparison property of integrals:
\If
for
, then
.
Here
and
.
Hence by the comparison property of integrals,
\
\
.