(a)
\The function is
.
\
A function
is said to be one to one if any two elements in the domain are correspond to two different elements in the range.
\
If
and
are two different inputs of a function
, then
is said to be one to one provided
.
If
then
.
Since
, the function
is said to be one-to-one function.
(b)The function is
.
Theorem 7: If
is a one to one differentiable function with inverse function
and
then the inverse function is differentiable at
and
.
Find
.
Equate the function to
.

Therefore
then
.

Differentiate the function with respect to
.
Power rule of derivatives :
.
.

.
(c)The function is
.
Let
.
\
To find the inverse of
, replace
with
and
with
.
\
Solve for 
.
.
The inverse of the function
is
.
Find the domain and range of
.
The domain of a function is all values of
, those make the function mathematically correct.
So, the domain of the inverse function is all real numbers.
\Domain of
is
.
Range set is the corresponding values of the function for different values of
.
The range of the function is also all real numbers.
\Range of
is
.
(d)
\The inverse function is
.
Differentiate the function with respect to
.
Apply power rule of derivatives :
.
\

\
Find
at
.
\

.
\
(e)
\\
The graph of
and
is :

(a) The function
is said to be one-to-one function.
\
(b)
.
(c)
\\
The inverse function is
,
Domain of
is
.
Range of
is
.
\
(d)
.
(e)
\The graph is :
\
.