\
(a)
\The definite integral is
.
Determine
by left end points:
Observe the graph of
.
Number of subintervals are
.
Width of the interval is :
.
Left end points are
and
.
Riemann sum is
.

.
Substitute corresponding function values in above expression from the graph.
\
Area under the graph of the function using left endpoints is
.
.
Determine
using right endpoints.
Number of subintervals are
.
Width of the interval is :
.
Right end points are
and
.
Riemann sum is
.

.
Substitute corresponding function values in above expression observe from the graph.
\
Area under the graph of the function using right endpoints is
.
.
Determine
by Mid points:
Number of subintervals are
.
Width of the interval is :
.
, where
.
Mid points are
and
.
Riemann sum is
.
.
Substitute corresponding function values in above expression from the given graph.
\
Area under the graph of the function using mid points is
.
.
\
(b)
\Consder the graph is approximately equal to sum of the area of the right angle triangle and rectangle.
\Area of the triangle is
.
From the graph,
and
.
Therefore, area of the graph is
\ 
Area of the rectangle is
.
.
Total area under the graph is 
Actual area of the graph is 8 units.
\Now compare
and
values with actual area value.
Therefore,
is an underestimate and
are over estimates.
\
(c)
\Find
:
Trapezoidal rule:
\
Where,
.

\
Substitute corresponding values in the above expression.
\
\
(d)
\For any value of
, the values of
and
.
Observe the results in step 1, 2, and 3.
\
.
\
(a)
\
,
and 
(b)
\
is an underestimate and
are over estimates.
\
(c)
(d)
\
.