$\"\"$

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If $\"\"$ and $\"\"$ .

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The integral expression is $\"\"$ .

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Consider the fact that $\"\"$ is greater than $\"\"$ , since denominator is small in the first expression.

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Consider $\"\"$ .

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$\"\"$

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Since $\"\"$ then $\"\"$ and it is some negative number.

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Let $\"\"$

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$\"\"$

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$\"\"$ which results a finite number, therefore $\"\"$ is convergent.

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From the comparison theorem:

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Suppose $\"\"$ and $\"\"$ are continuous functions with $\"\"$ and

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If $\"\"$ is convergent then $\"\"$ is also convergent.

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Therefore, if $\"\"$ then $\"\"$ is also convergent.

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$\"\"$

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$\"\"$ is convergent.