The equation is
.
(a) Find that the function is increasing when the condition is
.
Consider 



.
Consider
.



.
If
, then
and
.
Hence,
.
The value of
when
.
Therefore, the function is increasing when
.
Show that the function is decreasing when the condition is
.
If
, then
and
.
Hence the product is
.
Therefore, the function is decreasing when
.
(b)
\The function is
.
Substitute
in
.
Graph the differential equation
. \ \
Graph :
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Observe the graph:
\When,
the vaue of
.
the value of
.
the value of
.
Find the equilibrium solutions of the funtion.
\The equilibrium solutions occur when
.
Substitute
and equate the function to zero.


.
Equilibrium occurs when
.
(c)
\The function is
\ \




Apply integral on each side.
\



.
At the initial condiition
and
.


Substitute
in
.










.
Therefore , the solution is
.
(d)
\If
,show that atleast one value of
, the value of
.
The function is
.
Equate the function
.




When
, the value of
has atleast a single value for
.
(a) The function is increasing when
and the function is decreasing when
.
(b)
\ .gif\")
When
the vaue of
.
the value of
.
the value of
.
The Equilibrium conditions are
.
(c) The solution is
.
(d) The value of
have atleast a single value for
.