The differential equation is
.
The solution of the differential equation with
is
,
where
is the carrying capacity and
is called as learning curve.
Jim processed
units during first hour and
units during second hour.
Therefore two points are
and
.
The solution passes through
:

The solution passes through
:

Equate the equations
and
.


.
Therefore, Jim can process a maximum of
units per hour.
Mark processed
units during first hour and
units during second hour.
Therefore, two points are
and
.
The solution passes through
:

The solution passes through
:

Equate the equations
and
.



Therefore, Mark can process a maximum of
units per hour.
Jim can process a maximum of
units per hour.
Mark can process a maximum of
units per hour.