The integral is
.
The series is in the form of
.
The power series form of
is
.
The power series form of
.
Apply integral on each side.
\

.
Therefore, the power series is
.
The series is 
Consider
.


Substitute
in
.



If
then
.

The series is converges for
.
.
The radius of convergence is
.
Therefore, the power series is
and
.
The power series for
is
.



The function is
.
Tabulate the values for different values of
.
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The values of
.
.
Using power series
.
.