$\"\"$

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The line equation is $\"\"$ and the point is $\"\"$ .

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Show that the distance from a point $\"\"$ to the line $\"\"$ is $\"\"$ .

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The normalized vector parallel to the line $\"\"$ is $\"\"$ .

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The normalized vector parallel to the normal to the line is $\"\"$ .

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Hence the scalar product of the two equations is zero.

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Draw the related diagram :

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$\"\"$

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The point $\"\"$ is the any point on the line equation $\"\"$ .

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The distance $\"\"$ is the magnitude of proj of $\"\"$ on $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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Substitute $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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Therefore, the distance from a point $\"\"$ to the line $\"\"$ is $\"\"$ .

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$\"\"$

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The point is $\"\"$ .

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The line equation is $\"\"$ .

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The general form of line equation is $\"\"$ .

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Here $\"\"$ .

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The distance from a point $\"\"$ to the line $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$ .

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Therefore, the distance form a point $\"\"$ to the line $\"\"$ is $\"\"$ .

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$\"\"$

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The distance form a point $\"\"$ to the line $\"\"$ is $\"\"$ .