The parabolic cylinders equations are
and
and the point is
.
Let us assume
.
and
.
Therefore, the parametric equations are
,
and
.
for the point
is when
.
Consider
.
Apply derivative on each side.
\
.

.
.
.






.
The binomial vector is
.
Substitute
and
.

.
The binomial vector is
.
The normal vector is
.
Substitute
.

Substitute
and
.
.
The normal vector is
.
The normal plane has a normal vector
and the point is
.
The equation of the normal plane is 

The equation for normal plane is
.
The oscillating plane has a binomial vector
and the point is
.
The equation of the oscillating plane is 

Therefore, the equation of the osculating plane is
.
The equation for normal plane is
and the equation of the osculating plane is
.