(a)
\Motion of particle is
.
Find the velocity of particle by applying derivative.
\
Therefore the velocity of particle is
.
Equate it to zero.
\
So the critical numbers are
and
.
(b)
\Consider the test intervals to find the interval of increasing and decreasing.
\| Test interval | \Test value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
![]() | \
![]() | \
\
| \
Increasing | \
The sign of the velocity function is positive on the intervals
and
.
(c)
\The sign of the velocity function is negative on the intervals
.
(d)
\At
and
, the velocity function changes its sign.
(a) The velocity of particle is
.
(b) The sign of the velocity function is positive on the intervals
and
.
(c) The sign of the velocity function is negative on the intervals
.
(d) Velocity function changes its direction at
and
.