(a)
\The completed table :
\Height, ![]() | \
Length and Width, ![]() | \
Volume, ![]() | \
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Observe the above table :
\The maximum volume occurs at
, i.e,
.
(b)
\From the table :
\Volume of the box :
\
.
(c)
\Volume
.
Derivative on each side with respect to
.

Find the crirical numbers by equating derivative to zero.
\
and 
and
.
Thus, the critical numbers are
and
.
.
Derivative on each side with respect to
.

.
If
, then
.
By second derivative test,
is a maximum value.
Substitute
in
.
.
Thus, the maximum volume is
.
If
, then
.
By the second derivative test,
is a minimum value.
The volume function is
.
Draw a coordinate plane.
\Graph the function
.
Graph :
\
Observe the graph :
\The maximum volume occurs at
and the maximum volume is
.
(a)
\The completed table :
\Height, ![]() | \
Length and Width, ![]() | \
Volume, ![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
The maximum volume occurs at
, i.e,
.
(b)
\Volume
.
(c)
\The critical numbers are
and
.
The maximum volume is
.
(d)
\Graph of the function
:

The maximum volume occurs at
and the maximum volume is
.