Let
be the length of the rectangle and
be the width of the rectangle.
Area of the rectangle
.
Find
in terms of
.
Perimeter of the rectangle
.




Substitute
in
.

.
.
Differentiate on each side with respect to
.

Find the critical numbers by equating derivative to zero.
\



Substitute
in
.




Since the second derivative of
is negative, it gives a maximum.
is maximum when
and
.
There are no dimensions that yield a minimum area.
\Explanation :
\This can be made by arbitrary small by selecting
.
is maximum when
and
.
There are no dimensions that yield a minimum area.
\Explanation :
\This can be made by arbitrary small by selecting
.