The function is
and the point is
.

Apply derivative on each side with respect to
.

.
At the point
,
.
This is the slope of the tangent line.
\Slope of the tangent line is
.
Point-slope form of the line equation is
, where
is slope.
Substitute
and
in point-slope form.


The tangent line equation is
.
Use the linear approximation to complete the table.
\![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
| \
| \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
The table compares the values of
given by linear approximation with the values of
near
and
.
The tangent line equation is
.
The completed table :
\![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
| \
| \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \