$\"\"$

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(a)

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The function is $\"\"$ .

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Rewrite the function as $\"\"$ .

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Find the inverse function.

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$\"\"$

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Interchange the variables $\"image\"$ and $\"image\"$ .

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$\"\"$ .

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Squaring on each side.

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$\"\"$

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$\"\"$ .

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Substitute $\"\"$ .

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The inverse of the function is $\"\"$ .

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$\"\"$

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(b)

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Draw a coordinate plane.

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Graph the functions $\"\"$ and $\"\"$ in the interval $\"\"$ .

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$\"\"$

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Observe the graph :

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The functions $\"\"$ and $\"\"$ are symmetric about the line $\"\"$ .

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$\"\"$

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(c)

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Both the function and inverse function are same.

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The functions $\"\"$ and $\"\"$ are symmetric about the line $\"\"$ .

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$\"\"$

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(d)

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The function is $\"\"$ .

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The domain of a function is all values of $\"\"$ , those makes the function mathematically correct.

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The function under the square cannot be negative.

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The domain of the $\"\"$ is a set of all non negative real numbers.

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$\"\"$

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Since the function is defined in the interval $\"\"$ .

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Therefore, Domain of $\"\"$ is $\"\"$ .

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$\"\"$ .

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Therefore, Domain of $\"\"$ is $\"\"$ .

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The range of the function $\"\"$ is the domain of $\"\"$ .

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Thus the range of $\"\"$ is $\"\"$ .

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And the range of $\"\"$ is $\"\"$ .

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$\"\"$

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(a)

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The inverse function is $\"\"$ .

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(b)

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The graph of the functions are $\"\"$ and $\"\"$ in the interval $\"\"$ .

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$\"\"$

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(c)

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$\"image\"$ and $\"image\"$ are symmetric about $\"\"$ .

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(d)

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Domain of $\"\"$ is $\"\"$ .

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Range of $\"\"$ is $\"\"$ .

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Domain of $\"\"$ is $\"\"$ .

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Range of $\"\"$ is $\"\"$ .