The function is
,
.
The function appears to be continuous on the interval
.
To find the function is one-to-one function, differentiate
.


Since the derivative of the function is a positive value, the function is one to one function and is strictly monotonic.
\To find the inverse of the function, let us assume
and solve the x in terms of y.

Now interchange x and y, substitute
.
,
.
The function is
is one to one function and is strictly monotonic.
The inverse of
is
,
.