The equations are
,
,
and
.
The length of the beam is
.
The volume of the beam is
.
The area of the beam is
.
Substitutte
and
in
.


Substitute
.
Apply derivative on each side with respect to
.


.
If
and
.
Substitute
and
in
.


Substitute
and
.


Therefore, the volume of the beam is 
Find the weight of the beam.
\The density of the concrete is 
The weight of the beam is
.
Substitute corresponding values.
\

Therefore, the weight of the beam is 
(b)
\Find the centroid of the cross section of the beam.
\The centroid of the beam is
.
The beam is symmetric about
-axis, hence the value of the
.
The value of
.
Substitute
.
.
The value of 
.
Apply formula :
.


Substitute
and
in
.

.
Therefore, the centroid of the beam is
.
(a) The volume of the beam is
and the weight of the beam is 
(b) The centroid of the beam is
.