The function is
,
.
Horizontal asymptotes are horizontal lines that the graph of the function approaches as
tends to
or
.
The horizontal asymptote is
.
does not exist.
Therefore, there is no horizontal asymptote.
\Find the relative extrema.
\Consider
.


Apply derivative on each side with reaspect to
.




Find the critical points, by equating
.


cannot be zero.



.
The critical number is
.
Consider the test intervals to find the interval of increasing and decreasing.
\Test intervals are
and
.
| Test intervals | \ \
Test value \ | \
\
Sign of | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
| \
| \
![]() | \
\
| \
Increasing | \
The function
is decreasing on the interval
.
The function
is increasing on the interval
.
changes from negative to positive.
Therefore according to First derivative test, the function has minimum at
.
When
,
.
Therefore, the relative maximum is
.
Graph the function
.

No horizontal asymptote.
\The relative minimum is
.
Graph of the function
.
.