$\"\"$

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The integral is $\"\"$ .

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$\"\"$ is improper because the denominator $\"\"$ .

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$\"\"$

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$\"\"$ .

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The integral is undefined at $\"\"$ , which lies in the interval $\"\"$ .

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$\"\"$ has infinite discontinuity at $\"\"$ .

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$\"\"$

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If $\"\"$ is continuous on the interval $\"\"$ and has an infinite discontinuity at $\"\"$ , then $\"\"$ , the limit exists then function is convergent.

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$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$ .

\

Therefore, the integral is converges to $\"\"$ .

\

$\"\"$

\

$\"\"$ has infinite discontinuity at $\"\"$ .

\

The integral is converges to $\"\"$ .