$\"\"$

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The function is $\"\"$ .

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Find the surface area of the region formed by revolving the region on the $\"\"$ .

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Consider $\"\"$ .

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Differentiate on each side with respect to $\"\"$ .

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$\"\"$

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Area of surface of revolution formed by revolving the graph of $\"\"$ about horizontal or vertical axis is

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$\"\"$ .

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Where $\"\"$ is continuous function on interval $\"\"$ and $\"\"$ is the distance between the

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graph of $\"\"$ and axis of revolution.

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Here $\"\"$ .

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Substitute corresponding values.

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Therefore, $\"\"$ .

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$\"\"$ .

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$\"\"$

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Find the integral by substitution method.

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Consider $\"\"$

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Let $\"\"$

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$\"\"$

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Substitute corresponding values.

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$\"\"$ .

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Integral formula : $\"\"$ .

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$\"\"$

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Substitute back $\"\"$ .

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$\"\"$

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Substitute integral limits.

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$\"\"$

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$\"\"$ sq-units.

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$\"\"$

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Surface area of revolution is $\"\"$ sq-units.