The function is
in the interval
.

It follows that
and
.
we can therefore apply intermediate value theorem to conclude that there
\must be some c in
such that 
Now we use bisection method for approximating the real zeros of a continuous function.
\In this approximation if
, then the zero must lie in the interval
.
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
The approximated value of zero is
,
.
Now we have to find out zero value using graphical approach.
\.gif\")
From the above graph the zero value is nearly
, it is located between
and
.
To find out the accurate value of value we further need to zoom the graphing utility as shown below.
\(1).gif\")
We clearly observe from the above graph the zero value is nearly
.
The zero value approximated to two decimal points is
.
The zero value approximated to four decimal points is
.